Skip to end of metadata
Go to start of metadata

You are viewing an old version of this page. View the current version.

Compare with Current View Version History

« Previous Version 12 Next »

Diaphragm forces

1. Apply diaphragm forces (define diaphragm using semi-rigid option)


Unknown macro: {center-text}

Figure 1 - Apply diaphragm forces


2. Display any stress or shell force for the relevant load case


Unknown macro: {center-text}

Figure 2 - Display stress or shell force


3. For maximum chord forces, draw or define a section cut where maximum chord forces are expected


Unknown macro: {center-text}

Figure 3 - Maximum chord forces


4. Moments in Z are the in-plane moment in slab make sure angle is zero, refresh as required


Unknown macro: {center-text}

Figure 4 - In-plane moment


5. The value of Z moment divided by slab width is equal to compression and tension chord forces


Unknown macro: {center-text}

Figure 5 - Compression and tension chord forces


6. Shear and collector forces at slab-shear wall connection, draw or define section cut next to support following wall direction


Unknown macro: {center-text}

Figure 6 - Shear and collector forces


7. Make sure angle is zero, in this case shear/collector force is equal to F2 or 2559lbs as expected


Unknown macro: {center-text}

Figure 7 - Shear and collector forces

See Also

  • No labels