DIAPHRAGM FORCES
1.- Apply diaphragm forces (define diaphragm using semi-rigid option)
2.- Display any stress or shell force for the relevant load case
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5.- The value of Z moment divided by slab width is equal to compression and tension chord forces
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7.- Make sure angle is zero, in this case shear/collector force is equal to F2 or 2559lbs as expected
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h1. Diaphragm forces
1. Apply diaphragm forces (define diaphragm using semi-rigid option)
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{center-text}Figure 1 - Apply diaphragm forces{center-text}
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2. Display any stress or shell force for the relevant load case
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!worddavd26cf2b3a7f5b7dfb2c859960d4042b5.png|align=center,border=0!
{center-text}Figure 2 - Display stress or shell force{center-text}
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3. For maximum chord forces, draw or define a section cut where maximum chord forces are expected
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!worddavb9bce433f4a6f0d8da6c5b32e1a93d47.png|align=center,border=0!
{center-text}Figure 3 - Maximum chord forces{center-text}
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4. Moments in Z are the in-plane moment in slab make sure angle is zero, refresh as required
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!worddav2c11c3f891465985ec44e2e13afd6298.png|align=center,border=0!
{center-text}Figure 4 - In-plane moment{center-text}
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5. The value of Z moment divided by slab width is equal to compression and tension chord forces
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!worddav9f256fcb1daf7bef870b821873738f90.png|align=center,border=0!
{center-text}Figure 5 - Compression and tension chord forces{center-text}
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6. Shear and collector forces at slab-shear wall connection, draw or define section cut next to support following wall direction
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!worddav2be42fafeaac037a13a3e192ae5b9bc2.png|align=center,border=0!
{center-text}Figure 6 - Shear and collector forces{center-text}
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7. Make sure angle is zero, in this case shear/collector force is equal to F2 or 2559lbs as expected
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!worddavf803a2adef2e14e1dbddb699f388715e.png|align=center,border=0!
{center-text}Figure 7 - Shear and collector forces{center-text}
h1. See Also
* [Rigid vs. Semi-rigid Diaphragm|etabs:Rigid vs. Semi-rigid Diaphragm] |