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h1. Diaphragm forces

1. Apply\\

The collector forces within a diaphragm may be measured through the following process:

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1. Define a semi-rigid diaphragm, then apply diaphragm forces, (defineas diaphragmshown usingin semi-rigid option)Figure 1:

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{center-text}Figure 1 - Apply diaphragm forces{center-text}

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2. Display For a given [load case|kb:Load case], display any stress or [shell|kb:Shell] force, foras theshown relevantin loadFigure case2:

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{center-text}Figure 2 - Display stress or shell force{center-text}

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3. ForWhere maximum chord forces are expected,  draw or define a section cut, whereas maximumshown chordin forcesFigure are3:
expected

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{center-text}Figure 3 - Maximum chord forces{center-text}

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4. Moments inabout the Z-axis are therepresent in-plane momentmoments. inEnsure slabthat makethe sureresultant-force angle is zero, refreshthen select Refresh, as required shown in Figure 4:

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{center-text}Figure 4 - In-plane moment{center-text}

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5. The   Compression and tension chord forces are then given as the value of each Z-axis moment divided by slab width, isas equalshown toin compressionFigure and5:
tension
chord forces

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{center-text}Figure 5 - Compression and tension chord forces{center-text}

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6. ShearFor shear and collector forces located at slab- the connection between the diaphragm and a shear wall connection, draw or define a section cut next to the support which follows followingthe wall direction, as shown in Figure 6:

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!worddav2be42fafeaac037a13a3e192ae5b9bc2.png|align=center,border=0!

{center-text}Figure 6 - Shear and collector forces{center-text}

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7. Make sure Again, ensure that the resultant-force angle is zero, in and refresh as necessary. Given this caseexample model, the shear/collector force, which is equalpresented toin F2, or 2559lbsis 2559 lbs., as expectedshown in Figure 7:

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{center-text}Figure 7 - Shear and collector forces{center-text}


h1. See Also

* [Rigid vs. Semi-rigid Diaphragm|Rigid vs. Semi-rigid diaphragm]